Rezolvarea unei problemei la Agregate si Instalatii Termice
1) Compoziția amestecului combustibil dat prin temă: (22% gm; 60% gf; 18% gc ) % CH4 = (X CmHngm + Y CmHngf + Z CmHngc)·1/100 =(22∙99.98 + 60∙0 + 18∙28)/100 = 27.036 % C2H4 = (X CmHngm + Y CmHngf + Z CmHngc)·1/100 =(22∙0.02 + 60∙0 + 18∙2)/100 = 0.3644y % H2 = (X H2gm + Y H2gf + Z H2gc )·1/100 =(22∙0 + 60∙3 + 18∙52)/100 = 11.16 % N2 = (X N2gm + Y N2gf + Z N2gc )·1/100 =(22∙0 + 60∙59.5 + 18∙7.2)/100 = 36.996 % O2 = (X O2gm + Y O2gf + Z O2gc )·1/100 =(22∙0 + 60∙0 + 18∙0.5)/100 =...
Domeniu: Instalatii
